If 90 pounds are removed from Station 140, what is the new location of the CG for an aircraft weighing 6,230 lb with the CG located initially at Station 79?

If 90 pounds are removed from Station 140, what is the new location of the CG for an aircraft weighing 6,230 lb with the CG located initially at Station 79?

• A. 77.0
• B. 78.1
• C. 79.0
• D. 80.0

Answer: (B)

To determine the new location of the center of gravity (CG) after removing weight from Station 140, we need to apply the concepts of weight and moment calculations. Initially, the aircraft weighs 6,230 pounds and has its CG located at Station 79. The removal of 90 pounds means we need to consider the effect of this weight change on the overall moment of the aircraft. First, we find the moment about the reference point (usually Station 0) before the weight is removed: - The initial moment is calculated as the weight multiplied by the CG position: \(6,230 \text{ lb} \times 79 \text{ in} = 492,170 \text{ lb-in}\). Next, when 90 pounds are removed from Station 140: - The moment due to the removed weight is calculated as \(90 \text{ lb} \times 140 \text{ in} = 12,600 \text{ lb-in}\). Now, subtract the removed moment from the initial moment: - The new moment after removing the weight is \(492,170 \text{ lb-in} - 12,600 \text{ lb-in} = 479,570 \text{ lb-in}\).

To determine the new location of the center of gravity (CG) after removing weight from Station 140, we need to apply the concepts of weight and moment calculations.

Initially, the aircraft weighs 6,230 pounds and has its CG located at Station 79. The removal of 90 pounds means we need to consider the effect of this weight change on the overall moment of the aircraft.

First, we find the moment about the reference point (usually Station 0) before the weight is removed:

• The initial moment is calculated as the weight multiplied by the CG position: (6,230 \text{ lb} \times 79 \text{ in} = 492,170 \text{ lb-in}).

Next, when 90 pounds are removed from Station 140:

• The moment due to the removed weight is calculated as (90 \text{ lb} \times 140 \text{ in} = 12,600 \text{ lb-in}).

Now, subtract the removed moment from the initial moment:

• The new moment after removing the weight is (492,170 \text{ lb-in} - 12,600 \text{ lb-in} = 479,570 \text{ lb-in}).